iEthan
Member
So, I've created a script that sees if a XML file with the same name is in pgs/. If it is, it will grab the title and put it in $title, and grab the content and put it in $content. Now, I need to get $name. I've defined it in the test page. But, it is giving me the error that it is an undefined variable. But, I have defined it.
Perhaps I should give you the code:
display.php (the script that grabs the content and title)
index.php (the test page)
index.xml (the XML file that has the title and content.
It is giving me the undefined error for $name, but it is clearly defined in index.php. How do I work around this?
You may need clarification...
Perhaps I should give you the code:
display.php (the script that grabs the content and title)
PHP:
<?php
if(file_exists('pgs/' . $name . '.xml')){
$getXML = new DOMDocument();
$getXML->load('pgs/' . $name . '.xml');
$getPage = $getXML->getElementsByTagName("page");
foreach($getPage as $page){
$getTitle = $page->getElementsByTagName("title");
$title = $getTitle->item(0)->nodeValue;
$getContent = $page->getElementsByTagName("content");
$content = $getContent->item(0)->nodeValue;
}
}
?>index.php (the test page)
HTML:
<?php
include('../display.php');
$name = 'index';
?>
<html>
<head>
<title>LiteManage Test</title>
</head>
<body>
<h1><?php echo $title ?></h1>
<p><?php echo $content ?></p>
</body>
</html>index.xml (the XML file that has the title and content.
Code:
<?xml version="1.0"?><page> <title>Home</title> <content> Hello. My name is Ethan. </content></page>It is giving me the undefined error for $name, but it is clearly defined in index.php. How do I work around this?
You may need clarification...
